Breaking Down The Price Of Albert Haynesworth (in Lbs.)

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Breaking Down The Price Of Albert Haynesworth (in Lbs.)
(Photo by Mitchell Layton/Getty Images)

Have you ever walked into a grocery store and bought steak?

On your way out, did you ask yourself why you paid what you did for that steak?

Did you ever wonder the price per pound to acquire Albert Haynesworth?

Albert Haynesworth recently recieved a seven year, $100 million dollar contract. Albert Haynesworth also weights 320 pounds.

If we start by finding price per pound per year, we will take 100,000,000 and divide it by seven to get $14,285,714.29. After that we divide that number by 320, his weight, to get $44,682.46 per pound.

You'll never complain about the price of a steak again.

Now, to find the total for price per pound per his contract, we take 100,000,000 and divide it by 320 pounds to get $312,500 per pound.

Now, to get even more in depth, lets find the price per drive.

The average amount of drives per game is 11. First we multiply the number of drives, 11, by the number of regular season games, 16, to get 176.

Next, we take 176 and multiply it by seven to get the length of Albert Haynesworth's contract, 1232. After that, we take the $100,000,000 contract by the amount of drives during his contract, 1232, to get $81,168 per drive.

On average a drive is 6.6 downs. In order to find the price per down, we take the average number of drives per game, 11, and multiply it by the average number of plays per drive, 6.6, to get 72.6 downs per game.

Next we take the amount of downs per game, 72.6, and multiply it by the number of games during the regular season, 16, to get 1161.6 downs per season. After that, we take the 1161.6 downs per year and multiply it by his contract length, seven years, to get 8131.2 downs during his contract.

Take $100,000,000 and divide it by 8131.2 downs to get $12,299 per down.

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