Terry Stotts Says Golden State Warriors Will Finish with Best Record Ever

Mike ChiariFeatured ColumnistJanuary 9, 2016

Golden State Warriors guard Klay Thompson (11) drives to the basket on Portland Trail Blazers center Mason Plumlee (24) during the first half of an NBA basketball game in Portland, Ore., Friday, Jan. 8, 2016. (AP Photo/Steve Dykes)
Steve Dykes/Associated Press

Following a 20-point loss to the Golden State Warriors on Friday night, Portland Trail Blazers head coach Terry Stotts predicted the Dubs will make history in 2015-16.

According to Sean Michael Meagher of OregonLive.com, Stotts believes the defending NBA champions will win more games this season than any team has in NBA history:

Golden State is currently 34-2, which puts it on pace to surpass the Chicago Bulls' 72-10 record set in 1995-96.

Provided MVP candidate Stephen Curry can avoid further injury to his shin and key players like Klay Thompson, Draymond Green, Andre Iguodala and Harrison Barnes remain healthy as well, the Warriors have a great chance to make a run at the all-time mark.

Even if they do surpass the Bulls, though, TNT NBA analyst and Basketball Hall of Famer Charles Barkley has little doubt the Warriors wouldn't be able to stand up to that team on the court, according to what he said on ESPN Radio's Waddle and Silvy in December (h/t ESPN.com):

"That Bulls team would kill this little team," Barkley said. "Come on, man. Who is going to guard Scottie Pippen and Michael Jordan? What about Dennis Rodman?"

While it is possible Barkley is correct, basketball fans will never get to find out.

One thing that is for sure, though, is the Warriors are the best team in basketball, and it is difficult to find eight more losses on their remaining schedule.

Perhaps the most compelling argument against a record of 73-9 or better is the idea that Golden State could sit some players late in the season in preparation for the playoffs.

After all, the Dubs' ultimate goal is probably to repeat as NBA champions more so than set the wins record.


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